论文标题
A = 15核中单粒子强度的淬灭
Quenching of Single-Particle Strength in A=15 Nuclei
论文作者
论文摘要
在$^{14} $ c和$^{14} $ n添加$ s $ - 和$ d $ - 波中子的绝对交叉部分已通过（$ d $，$ p $）以10 meV/u的反应同时确定。 $^{14} $ C $+$+$+$+$+$+$+$+$+$+$+$+8 $ meV之间的中子和质子分离能之间的差异约为$ -20 $ MEV，对于$^{14} $ n $+$+$+$$ n $。与独立的单粒子模型相比，两种系统的$ 1S_ {1/2} $和$ 0D_ {5/2} $轨道的总体减少了约0.5倍，而与Shell Model相比，降低了约0.6。这一发现与从$^{9} $ be和$^{12} $ c的目标核之间的中间能源敲除反应推导出的结果强烈形成鲜明对比。所使用的同时技术消除了许多系统的不确定性。
Absolute cross sections for the addition of $s$- and $d$-wave neutrons to $^{14}$C and $^{14}$N have been determined simultaneously via the ($d$,$p$) reaction at 10 MeV/u. The difference between the neutron and proton separation energies, $ΔS$, is around $-20$ MeV for the $^{14}$C$+$$n$ system and $+8$ MeV for $^{14}$N$+$$n$. The population of the $1s_{1/2}$ and $0d_{5/2}$ orbitals for both systems is reduced by a factor of approximately 0.5 compared to the independent single-particle model, or about 0.6 when compared to the shell model. This finding strongly contrasts with results deduced from intermediate-energy knockout reactions between similar nuclei on targets of $^{9}$Be and $^{12}$C. The simultaneous technique used removes many systematic uncertainties.
